A74.0-gram piece of metal at 94.0 °c is placed in 120.0 g of water in a calorimeter at 26.5 °c. the final temperature in the calorimeter is 32.0 °c. determine the specific heat of the metal. show your work by listing various steps, and explain how the law of conservation of energy applies to this situation.

Explanation:

The guiding principle in calorimetry is the Law of Conservation of Energy: the sum of all the energy transfers must add up to zero. That is,

q₁ + q₂ + … = 0

The formula for the heat q gained or lost by a substance is

q = mCΔT

where

m = the mass of the substance.

 C = its specific heat capacity.

ΔT = the change in temperature.

In this problem, there are two heat transfers: the heat lost by the metal and the heat gained by the water.

m₁C₁ΔT₁ + m₂C₂ΔT₂ = 0

Data:

m₁ = 74.0 g;   T₁ = 94.0 °C; T₂ = 32.0 °C

m₂ = 120.0 g; T₁ = 26.5 °C; T₂ = 32.0 °C

Calculations:

ΔT₁ = 32.0 - 94.0 = -62.0 °C

ΔT₂ = 32.0 - 26.5 =    5.5 °C

explanation:

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here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.

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