Fill in the coefficients that will balance the following reaction: a0ch3oh + a1o2 → a2co2 + a3h2o

a0=2

a1=3

a2=2

a3=4

Explanation:

The balanced equation for the complete combustion of methane is:

2CH₃OH₍l₎ + 3O₂₍g₎  → 2CO₂ + 4H₂O₍l₎

This way, there is an equal number of atoms of each kind on both reactants side and the products side.

Therefore the coefficients represented by the unknowns are:

a0=2

a1=3

a2=2

a3=4

The above is the equation for the complete combustion of methanol.

To find the number of atoms of each element we multiply coefficient × subscript  

For example   contains  

5 × 1 = 5 ,Ca atoms and

5 × 2 = 10, Cl atoms  

If there is a bracket in the chemical formula  

For example we multiply coefficient × subscript × number outside the bracket.......... to find the number of atoms  (Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So 3 × 3 = 9, Ca atoms  

3 × 1 × 2 = 6, P atoms  

3 × 4 × 2 = 24, O atoms are present.

Let us balance the equation  

 (Unbalanced)

Reactant Side       # of atoms of each element      Product Side

1                                             C                                           1

4                                            H                                           2

3                                            O                                           3

Multiplying CH3OH by 2 we will have 2 - C, 8 - H and 6 - O on the reactant side so the equation changes to  

 (Unbalanced)

Reactant Side       # of atoms of each element      Product Side

2                                            C                                           1

8                                            H                                           2

4                                             O                                           3

By multiplying by 2 and by 4 we will have

 (Unbalanced)

Reactant Side       # of atoms of each element      Product Side

2                                            C                                           2

8                                            H                                           8

4                                             O                                           8

To balance O atoms on the left we multiply O_2  by 3

 (balanced)(Answer)

Reactant Side       # of atoms of each element      Product Side

2                                            C                                           2

8                                            H                                           8

8                                             O                                           8

Balanced!!!

false

because it does not have the potential to be entirely used up