If 2.06 ml of seawater contains about 0.446 moles of gold, how many atoms of gold are in that volume of seawater?

2.69 x 10²³ atoms

Explanation:

Given parameters:

Volume of sea water = 2.06mL

number of moles of gold = 0.446moles

unknown:

Number of atoms in the sea water

Solution:

The mole is a convenient unit of measuring quantities of particles. In a mole we have 6.02 x 10²³particles.

The mole can be defined as the amount of a substance contained in Avogadro's number of particles which is 6.02 x 10²³particles.

Here, the particles we want to determine is the number of atoms:

Number of atoms is given as:

   Number of gold atoms = number of moles of gold x 6.02 x 10²³

  Number of gold atoms = 0.446 x 6.02 x 10²³ = 2.69 x 10²³ atoms

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

the answer is true.