You are given 50.0 ml of 1.50 m hno3. how many ml of 0.81 m naoh are needed to neutralize it?

V(HNO₃) = 50.0 mL in liters = 50.0 /1000 =0.05 L
M(HNO₃) = 1.50 M

Number of moles HNO₃ :

n = M x V

n = 1.50 x 0.05

n = 0.075 moles of HNO₃

HNO₃ + NaOH = H₂O + NaNO₃

1 mole HNO₃ ---1 mole NaOH
0.075 moles HNO₃ ?

moles NaOH = 0.075 * 1 / 1

 = 0.075 moles of NaOH

V ( NaOH ) :

M = n / V

0.81 = 0.075 / V

V = 0.075 / 0.81

V = 0.0925 L or  92.5 mL 

hope this helps!

I’m pretty sure it’s false i’m not sure