If 50.0 ml of 0.0160 m mercury(ii) nitrate is combined with 23.0 ml of 0.120 m sodium sulfide, what is the resulting concentration of sodium ions in the solution after the reaction is complete? (assume the solution volumes are additive). the balanced equation for the reaction is:

0.076M

Explanation:

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Just some clarifications:

- the moles of sodium cations qre computed from the moles of sodium sulfide, taking into account that 2 mol of sodium atoms are present per mole of sodium sulfide.

- the volumes of the solutions must be added to get the total one.

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answer: c. the experiment shows that the red substance experienced a chemical change.

explanation: chemical change is the change in which chemical composition of the substance changes. physical change is the change in which there is no change in chemical composition.

chemical changes are accompanied by following changes:

a) precipitate formation

b) energy is released or absorbed

c) formation of bubbles

d) change in color

as it is given that the red color has disappeared and there is production of gas, it means the red substance has undergone a chemical change.

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