if 20.15 ml of 0.150 m ammonium hydroxide is required to neutralize 13.5 ml of sulfurous acid, what is the molarity of the acid?
h2so3(aq)+2nh4oh(aq)→(nh4)2so3(aq)+ 2h2o(l)

The molarity of the acid is 0.112 M

Explanation:

In the reaction of neutralization, 2 moles of NH₄OH react with 1 mol H₂SO₃. Then, in the equivalence point, the number of moles of NH₄OH will be twice the number of moles of H₂SO₃.

In the equivalence point:

moles H₂SO₃ = 1/2 * moles NH₄OH

Then, let´s calculate the number of moles of NH₄OH consumed in the reaction:

number of moles = molar concentration * volume (l)

number of moles NH₄OH = 0.150 mol/l * 0.02015 l = 3.02 x 10⁻³ mol  

Then, the number of moles of H₂SO₃ will be:

moles H₂SO₃ = 1/2 * moles NH₄OH

moles H₂SO₃ = 1/2 * 3.02 x 10⁻³ mol  

moles H₂SO₃ = 1.51 x 10⁻³ moles

Since this number of moles was initially in 13. 5 ml, the concentration of H₂SO₃  will be:

molar concentration = number of moles / volume (l)

molar concentration =  1.51 x 10⁻³ moles / 0.0135 l = 0.112 M  

Have a nice day!

answer:

the reaction is type of combination reaction.

explanation:

on the product side, there are 2 molecules of bonded to fe   which means one atom of fe are combined two molecules of . so, balanced chemical equation becomes :

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.

answer: they produce more slow than unicellular organisms.