How many grams of nai are needed to prepare 400.0 ml of 0.0500 m nai solution?

We need 3.00 grams NaI

Explanation:

Step 1: Data given

Volume = 400.0 mL = 0.400L

Molarity = 0.0500 M

Molar mass of NaI = 149.89 g/mol

Step 2: Calculate moles

Moles NaI = molarity * volume

Moles NaI = 0.0500 M * 0.400 L

Moles NaI = 0.02 moles

Step 3: Calculate mass NaI

Mass NaI = moles NaI * molar mass NaI

Mass NaI = 0.02 moles * 149.89 g/mol

Mass NaI = 3.00 grams

We need 3.00 grams NaI

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