Write the balanced equation for the reaction that occurs when methanol, cheoh () is burned in air. what is the coefficient of oxygen in the balanced equation? a) 1 b) 2 c) 3 d) 4 e) 3/2

The balanced equation for methanol when is burned in the air, is

CH3OH + O2 >  3/2 CO2  +2 H2O and as you see coefficient of oxygen is 3/2

Explanation:

When you always burn something you are doing combustion. The reactives are your compound + O2, and as products you have CO2 and H2O

The coefficient of oxygen is 3 ( option c)

Explanation:

Methanol = CH3OH

The process of burning = adding oxygen (O2)

In this process methanol will be consumed and CO2 and H2O will be produced.

CH3OH + O2 → CO2 + H20

First we'll balance on both sides all H-atoms: left we have 4x H and on the right side we have 2x H so we have to multiply the right side ( H2O) by 2.

This gives us:   CH3OH + 02 → CO2 + 2 H2O

Since we have now, 3x O on the left side and 4x O on the right side, it looks like we don't have to multiply H2O on the right side by 2 but by 4, and then we multiply CH3OH on the left side by 2

This gives us: 2 CH3OH + O2 → CO2 + 4H2O

Now we have on both side 8x H

On the left side we have 2x C, and 1x C on the right side. So we have to multiply CO2 on the right side by 2

This gives us: 2 CH3OH + O2 → 2 CO2 + 4H20

Now we have on both side 8x H and 2x C

On the left side we have 4x O but on the right side we have 8x O

We have to multiply O2 on the left side by 3, to equal this.

So finally, we'll have

2 CH3OH + 3O2 → 2 CO2 + 4H2O

This shows us that the coefficient of oxygen is 3 ( option c)

the cold front replaces the warmer air at the ground level changing the wind to be breezy and denser.there is also an immediate drop in the temperature.

yes the answer is total mass in unchanged   : )