The antacid component of tumsr is calcium carbonate. assume tumsr is 40.0 percent caco3 by mass. if we have 400. mg of tumsr how many ml of 0.100 m hcl can we neutralize? express your answer in ml.

31.9724 mL

Explanation:

The given antacid, Tumsr contains 40% of by mass.

Given mass of Tusmr = 400 mg

Mass of =

Also, 1 mg = 0.001 g

Mass of in Tusmr = 0.16 g

Molar mass of = 100.0869 g/mol

Moles = Mass / Molar mass = 0.16 g / 100.0869 g/mol = 15.9862 × 10⁻⁴ moles

Considering the reaction:

1 mole of react with 2 moles of HCl

15.9862 × 10⁻⁴ moles of react with 2*15.9862 × 10⁻⁴ moles of HCl

Moles of HCl = 31.9724 × 10⁻⁴ moles

Considering:

Or,

Given :

For HCl :

Molarity = 0.100 M

Let, Volume = x mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = x ×10⁻³ L

Moles of HCl =  31.9724 × 10⁻⁴

Volume = x = 31.9724 mL

fire could start, buildings collapsing, and ash falling from the sky.

explanation:

this is because the buildings or plants could catch on fire and the buildings would most likely collapse. lastly ash would fall because all the burning would cause ash to fall from the sky.

hope this .

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