Hellmann, zelles, palojarvi, and bai published a paper in 1997 about extracting lipids from organic material. they reported using a mixture that was 85% n-hexane and 15 % dichloromethane (vol/vol). what is the mole fraction of each compound in the mixture? what is the mass fraction of each compound in the mixture? skills: unit conversions, choosing a temporary basis

Mass fraction: 73,6% n-hexane; 26,4% dichloromethane

Mole fraction: 73,0% n-hexane; 27,0% dichloromethane

Explanation:

With a basis of 100 mL:

Mass of n-hexane:

85 mL × = 55,7 g

Mass of dichloromethane

15 mL × = 20,0 g

Total mass = 20,0 g + 55,7 g = 75,7 g

Mass fraction of n-hexane:

=73,6%

Mass fraction of dichloromethane:

= 26,4%

Moles of n-hexane:

55,7 g × = 0,65 moles

Mass of dichloromethane

20,0g × = 0,24 moles

Total moles: 0,65 moles + 0,24 moles = 0,89 moles

Molar fraction of n-hexane:

=73,0%

Molar fraction of dichloromethane:

= 27,0%

I hope it helps!

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be