Consider the relationship (y+3)2 = b/(x-2), where y and x are variables and bis a constant. on rectangular coordinate paper, what is the slope of a graph of in(y+3) on the vertical axis versus in(x-2) on the horizontal axis?

(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.

Explanation:

Taking natural logarithm on both the sides:

Slope intercept form is generally given as:

m = slope, c  = intercept on y axis or vertical axis

On rearranging equation:

y = ln [(y+3)], x = ln [(x-2)], m=-1 , c  = ln 2b

(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.

i believe it is 40–40–20%

explanation:

let that person have a turn to speak : )