Achemical process requires 7.300 g-mol of calcium sulfate (caso.) for a reaction. how many grams are in 7.300 g-mol of calcium sulfate? caso

The mass of copper sulfate is 1165 grams.

Explanation:

We are given:

Number of gram-moles of copper sulfate = 7.300 g-mol

We know that:

1 g-mol = 1 mol

So, number of moles of copper sulfate = 7.300 mol

To calculate the number of moles, we use the equation:

Molar mass of copper sulfate = 159.6 g/mol

Moles of copper sulfate = 7.300 moles

Putting values in above equation, we get:

Hence, the mass of copper sulfate is 1165 grams.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.