I’ll you : )
what is the mass of co2 produced when 100. g of butane, c4h10, is burned with excess oxygen,
according to the following chemical equation? (molar mass of c4h10 is 58.12 g/mol, molar mass of
co2 is 44.01 g/mol)
2 c4h10 (g) + 13 o2 (g) → 8 co2 (g) + 10 h20 (l)

The answer to your question is: 303g of CO2

Explanation:

Data

mass CO2 = ?

mass C4H10 = 100 g

MW C4H10 = 58.12 g

MW CO2 = 44.01 g

Solve this problem using rules of three

Reaction

                    2 C4H10 (g) + 13 O2 (g) → 8 CO2 (g) + 10 H20 (l)

                    2(58.12)       8(44.01)

                    100g              x

mass of CO2 produced = x = (100)(8)(44.01) / (2)(58.12)

                                          x = 35208 / 116.24

                                          x = 302.9 g ≈ 303 g of CO2

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.