What is the equilibrium partial pressure of water vapor above a mixture of 62.9 g h2o and 33.2 g hoch2ch2oh at 55 °c. the partial pressure of pure water at 55.0 °c is 118.0 mm hg. assume ideal behavior for the solution.

Answer : The partial pressure of is 102.3 mmHg.

Explanation :

As per question,

Mass of = 62.9 g

Mass of = 33.2 g

Molar mass of = 18 g/mole

Molar mass of = 62 g/mole

First we have to calculate the moles of and .

Now we have to calculate the mole fraction of and .

Now we have to partial pressure of .

According to the Raoult's law,

where,

= partial pressure of water vapor

= total pressure of gas

= mole fraction of water vapor

Therefore, the partial pressure of is 102.3 mmHg.

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