Menthol, the substance we can smell in mentholated cough drops, is composed of c, h, and o. a 6.030×10−2 −mg sample of menthol is combusted, producing 0.1697 mg of co2 and 6.954×10−2 mg of h2o. what is the empirical formula for menthol?

The empirical formula is =

Explanation:

Mass of water obtained =

Also, 1 mg = g

So, mass of water =

Molar mass of water = 18 g/mol

Moles of = /18 g/mol =  3.8634×10⁻⁶ moles

2 moles of hydrogen atoms are present in 1 mole of water. So,

Moles of H = 2 x 3.8634×10⁻⁶ = 7.7267×10⁻⁶ moles

Molar mass of H atom = 1.008 g/mol

Mass of H in molecule = 7.7267×10⁻⁶ x 1.008 = 7.6653×10⁻⁶ g

Mass of carbon dioxide obtained = 0.1697 mg

Also, 1 mg = g

So, mass of carbon dioxide =

Molar mass of carbon dioxide = 44.01 g/mol

Moles of =  /44.01 g/mol = 3.856×10⁻⁶ moles

1 mole of carbon atoms are present in 1 mole of carbon dioxide. So,

Moles of C = 3.856×10⁻⁶ moles

Molar mass of C atom = 12.0107 g/mol

Mass of C in molecule = 3.856×10⁻⁶ x 12.0107 = 46.3132 ×10⁻⁶ g

Given that the Menthol only contains hydrogen, oxygen and carbon. So,

Mass of O in the sample = Total mass - Mass of C  - Mass of H

Mass of the sample =

Also, 1 mg = g

So, mass of sample =

Mass of O in sample = ( 60.30 - 7.6653 - 46.3132 ) ×10⁻⁶ g= 6.3215×10⁻⁶ g

Molar mass of O = 15.999 g/mol

Moles of O  = 6.3215×10⁻⁶  / 15.999  = 0.3951×10⁻⁶ moles

Taking the simplest ratio for H, O and C as:

7.7267×10⁻⁶ : 0.3951×10⁻⁶ : 3.856×10⁻⁶

= 20 : 1 : 10

The empirical formula is =

smooth muscle is composed of involuntary muscles found within the walls of organs and structures such as the esophagus, stomach, intestines, and blood vessels. those muscles push materials like food or blood through organs. unlike skeletal muscle, smooth muscle can never be under your control.

2b2t

explanation:

2b2t