Achemistry student needs 50.0 g of methyl acetate for an experiment. by consulting the crc handbook of chemistry and physics, the student discovers that the density of methyl acetate is 0.934 g. cm . calculate the volume of methyl acetate the student should pour out. round your answer to 3 significant digits. x s ?

Explanation:

As density is defined as the mass of a substance divided by its volume.

Mathematically,         Density =

It is given that mass is 50 g and density is 0.934 .

Hence, calculate the volume of methyl acetate as follows.

                     Density =

             0.934 =

                       Volume =

or,                                  =                (as 1 = 1 mL)

Thus, we can conclude that the volume of methyl acetate the student should pour out is .

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :