Avoltaic electrochemical cell consists of a copper electrode in a cu2so4(aq) solution, and a palladium electrode in a pdso4(aq) solution at 25°c. the salt bridge consists of a solution of kcl(aq).

what is the concentration of the cu+if the concentration of the pdso4 is 0.498 m and the measured cell potential is 0.447 v?

given: cu+(aq) + e- ↔ cu(s) e°=+0.521 v

and pd2+(aq) + 2e- ↔ pd(s) e°=+0.987 v

Explanation:

We must use the Nernst equation

1. Calculate E°

Anode:     Pd²⁺ (0.498 mol·L⁻¹) + 2e⁻ ⇌ Pd;                               E° = +0.987 V

Cathode: Cu ⇌ Cu⁺ (x mol·L⁻¹) + e⁻;                                          E°=  - 0.521 V

Overall:   Pd²⁺(0.498 mol·L⁻¹) + 2Cu ⟶ Pd + 2Cu⁺ (x mol·L⁻¹); E° =   0.466 V

2. Calculate Q

3. Calculate [Cu⁺]

the answer is either b or c

i do not get it   at all