How many moles of solute particles are present in 4.98 ml of 0.72 m (nh4)2so4? when you have your answer, take the log (base 10) of your answer and enter it with 2 decimal places.

The number of moles of ammonium sulfate is 0.0036 moles and its logarithmic value is -2.44

Explanation:

To calculate the number of moles for given molarity, we use the equation:

Molarity of ammonium sulfate solution = 0.72 M

Volume of solution = 4.98 mL

Putting values in above equation, we get:

Taking the log (base 10) of the calculated moles of ammonium sulfate we get:

Hence, the number of moles of ammonium sulfate is 0.0036 moles and its logarithmic value is -2.44

sorry idk the answer well to you i have a explaination

explanation: a formula which shows the arrangement of atoms in the molecule of a compound