Gaseous hydrogen iodide is placed in a closed container at 425°c, where it partially decomposes to hydrogen and iodine: 2hi(g)⇌h₂(g)+i₂(g) at equilibrium it is found that [hi]= 3.51×10⁻³ m, [h₂]= 4.76×10⁻⁴ m, and [i₂]= 4.76×10⁻⁴ m.
what is the value of at this temperature? express the equilibrium constant to three significant digits.

Answer : The value of at this temperature is 0.0184

Explanation : Given,

Concentration of at equilibrium =

Concentration of at equilibrium =

Concentration of at equilibrium =

The given equilibrium reaction is,

The expression of will be,

Now put all the given values in this expression, we get:

Therefore, the value of at this temperature is 0.0184

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.