Ideal he gas expanded at constant pressure of 3 atm until its volume was increased from 9 liters to 15 liters. during this process, the gas absorbed 800j of heat from the surroundings. calculate the internal energy change of the gas, ae.

Explanation:

The given data is as follows.

             P = 3 atm

                =  

                 =

    = 9 L =    (as 1 L = 0.001 ),  

        = 15 L =

            Heat energy = 800 J

As relation between work, pressure and change in volume is as follows.

                  W =

or,                W =

Therefore, putting the given values into the above formula as follows.

                  W =

                      =

                      = 1823.85 Nm

or,                   = 1823.85 J

As internal energy of the gas is as follows.

                      = Q - W

                                  = 800 J - 1823.85 J

                                  = -1023.85 J

Thus, we can conclude that the internal energy change of the given gas is -1023.85 J.