Calculate the molarity of 0.400 mol of na, s in 1.30 l of solution. molarity: calculate the molarity of 23.9 g of mgs in 843 ml of solution. molarity:

The molarity of sodium sulfide and magnesium sulfide solution is 0.308M and 0.503 M respectively.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

   .....(1)

Or,

    ......(2)

Moles of sodium sulfide = 0.400 moles

Volume of solution = 1.30 L

Putting values in equation 1, we get:

Hence, the molarity of sodium sulfide solution is 0.308 M

Mass of MgS = 23.9 g

Molar mass of MgS = 56.4 g/mol

Volume of solution = 843 mL

Putting values in equation 2, we get:

Hence, the molarity of magnesium sulfide solution is 0.503 M

fe 55.85 g/mol and h2o 18.02 g/mol.

c. is the answer

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