Cyclopropane, c3h6, is used as a general anesthetic. if a sample of cyclopropane stored in a 2.36-l container at 10.0 atm and 25.0°c is transferred to a 7.79-l container at 5.56 atm, what is the resulting temperature? enter your answer in the provided box

Explanation:

The given data is as follows.

      = 2.36 L,     = = (25 + 273) K = 298 K,

      = 10.0 atm,    = 7.79 L,

        = ?,       = 5.56 atm  

And, according to ideal gas equation,  

Hence, putting the given values into the above formula to calculate the value of final temperature as follows.          

            = K

                     = 546.87 K

Thus, we can conclude that the final temperature is 546.87 K.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.