If 5.00 g helium gas is added to a 1.00 l balloon containing 1.00 g of helium gas, what is the new volume of the balloon? assume no change in temperature or pressure. enter your answer in the box provided. l

Explanation:

The given data is as follows.

                  = 5 g,         = 1 L

                  = 1 g,         = ?

No. of moles of helium present in 5 g helium gas are as follows.

                   No. of moles =

                                         =  

                                         = 1.25 mol

No. of moles of helium present in 1 g helium gas are as follows.

                 No. of moles =

                                         =  

                                         = 0.25 mol

According to the ideal gas equation, PV = nRT. And, since temperature and pressure are held constant. Therefore,

                              = 0.2 L

Thus, we can conclude that the new volume of the balloon is 0.2 L.

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation:

i'm pretty sure it is letter c.) car