How many grams do 6.7×1023 atoms of argon weigh?

44.4g

Explanation:

First we must find the moles of argon.

To do this, divide the number of atoms by Avogadro's number (6.022 ×10^23)

n= (6.7 × 10^23)/(6.022 × 10^23)

n=1.11258718034

Now to find mass, we complete the calculation

m= n × MM

where

m is mass

n is moles

MM is molecular mass

m= 1.11258718034 × 39.948

m= 44.4456326802

m= 44.4g

b. acid is the correct answer @jayxboof all social media

acid : acids are those which accepts an electron-pairs.

base : bases are those which donates ab electron-pairs.

alkali : it is a base that dissolves in water. it is basically a base and the ph greater than 7.

hydroxide ion : it is a poly-atomic ion which is negatively charged.