Riley discovered pure gold has a density of 19.32 g/cm3.what would the volume for a piece of gold be if it had a mass of 318.97 g?

The volume for a piece of gold that has the mass of 318,67 g is 16,50cm3

Explanation:

Density = mass / volume

Volume = mass/ density

Volume = 318,97 g / 19,32 g/cm3 = 16,50cm3

The volume of a gold piece  is

Explanation:

Given:

Density of  pure gold,  

Mass of the gold piece,

To Find:

The volume for a piece of gold whose mass is  

Solution:

The formula for density is:

where,

D is density,

M is mass,  

V is volume.

The above formula can be rewriiten as

Substituting the values ,we get

Taking multiplicative inverse of density , we have

Result:

Thus the volume of gold piece weighing 318.97 g is

nacl is added to the aqueous of what? ? in order to get a proper answer you have to specify the exact composition of the aqueous solution.

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be