Asample of gas under 3k pa pressure has a volume of 13 l at 56.12 kelvin. if the pressure is increased to 70 kpa the volume would decrease to 7 liters what would be the new temperature

The new temperature would be 705.1 K.

Explanation:

Given data:

Initial pressure = 3 kpa

Initial volume = 13 L

Initial temperature = 56.12 K

Final pressure = 70 Kpa

Final volume = 7 L

Final temperature = ?

Solution:

To solve this problem we will use the general gas equation.

P₁V₁/T₁   = P₂V₂/T₂

T₂ = P₂V₂ T₁/ P₁V₁

T₂ =  70 Kpa . 7 L . 56.12 K / 3 Kpa . 13 L

T₂ =  27498.8 / 39

T₂ = 705.1 K

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