Aclosed, rigid tank contains a two‐phase liquid–vapor mixture of refrigerant 22 initially at −20°c with a quality of 50.36%. energy transfer by heat into the tank occurs until the refrigerant is at a final pressure of 6 bar. determine the final temperature, in °c. if the final state is in the superheated vapor region, at what temperature, in °c, does the tank contain only saturated vapor?

Explanation:

The given data is as follows.

      Initial temperature of the system () =

So, at state 1 quality of the system is () = 0.5036

     Pressure at state 2, () = 6 bar

As, it is a rigid tank hence, the specific volumes at state 1 and state 2 are equal.

So,      

Now, from the saturated refrigerant-22 table taking specific volume at is as follows.

Thus,    

                       =

                       = 0.0007427 + 0.5036 (0.0926 - 0.0007427)

                       =

Hence,   =

Super heated refrigerant-22 tables take pressure at 6 bar. Interpolation method used to find the temperature is as follows.

                 and      

                  and

                    =

                    = 40 + 3.75

                    =

Saturated vapor refrigerant-22 takes specific volume at .

Therefore, interpolation method used to find the temperature will be as follows.

                   and    

                   and        

                               =

                          = -1.45 + 1.50

                          =

Thus, we can conclude that at tank contains only saturated vapor.

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