Calculate the volume of 1.0 m hcl required to react this amount of calcium carbonate as described in equation 1 in the background section. c) compare the volume of hcl calculated with the volume described in the procedure. will the amount of hcl used allow for calcium carbonate to be the limiting reactant?

its first and third is your answer i did the qustion the fourth isnt right

your answer is c) plasma

~*"auba14"*~

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.