Apure gold ring (c = 0.128 j/g°c) and pure silver ring (c = 0.235 j/g°c) have a total mass of 16.891 g . the two rings are heated to 66.887 oc and dropped into a 13.9 ml of water at 21.9 oc. when equilibrium is reached, the temperature of the water is 24.2 oc. what is the mass of gold ring? (assume a density of 0.998 g/ml for water.)

Explanation:

The total mass will be as follows.

          Total mass = mass of silver ring + mass of gold ring

And, heat lost by gold and silver rings = heat gained by water

  =

            = 133.368

              = 3.124

              = 3.124

        = 3.124                

                            = 7.897 g

Thus, we can conclude that the mass of gold ring is 7.897 g.

the answer is c.the valence of the atoms combine .