Calculate the mass of precipitate that will form if 0.75 l of 0.50 m lead nitrate is mixed with 0.850 l of concentrated sodium bromate. ksp for lead bromate = 7.9 x 10-6.

Answer : The mass of formed is 164.4 grams.

Explanation :

The balanced chemical reaction will be,

First we have to calculate the moles of .

From the balanced chemical reaction we conclude that,

Moles of = Moles of = 0.375 mole

The moles of precipitate formed = 0.375 mole

Now we have to calculate the moles of that dissolve in .

The dissociation of lead bromate is written as:

The expression for solubility constant for this reaction will be,

Total volume of the solution = 0.75 + 0.850 = 1.60 L

The moles of that dissolve in = 0.020 mole

The moles of precipitate formed = 0.375 - 0.020 = 0.355 mole

Now we have to calculate the mass of formed.

Therefore, the mass of formed is 164.4 grams.

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.