If you have 0.50 grams of p-aminophenol, how many mls of water will be needed if you are adding 20 molar equivalents? how many mls acetic anhydride will be required if you are adding 1.5 molar equivalents?

The volume of water required is 1.65 mL and the volume of acetic anhydride required is 0.65 mL

Explanation:

To calculate the number of moles, we use the equation:

     .....(1)

Given mass of p-aminophenol = 0.50 g

Molar mass of p-aminophenol = 109.14 g/mol

Putting values in equation 1, we get:

To calculate volume of solution, we use the equation:

      ......(2)

It is given that 20 molar equivalent so p-aminophenol is added:

Moles of water =

Mass of water is calculated by using equation 1, we get:

Molar mass of water = 18 g/mol

Mass of water =

Now, calculating the volume of water by using equation 2, we get:

Density of water = 1 g/mL

Mass of water = 1.65 g

Putting values in equation 2, we get:

Hence, the volume of water required is 1.65 mL

It is given that 1.5 molar equivalent so p-aminophenol is added:

Moles of acetic anhydride =

Mass of acetic anhydride is calculated by using equation 1, we get:

Molar mass of acetic anhydride = 102.1 g/mol

Mass of acetic anhydride =

Now, calculating the volume of acetic anhydride by using equation 2, we get:

Density of acetic anhydride = 1.08 g/mL

Mass of acetic anhydride = 0.701 g

Putting values in equation 2, we get:

Hence, the volume of acetic anhydride required is 0.65 mL