For a certain chemical reaction, the standard gibbs free energy of reaction at 10.0 °c is 149. kj. calculate the equilibrium constant k for this reaction to 2 significant digits. round your answer k ?

The equilibrium constant for this reaction is

Explanation:

To calculate the equilibrium constant (at 15°C) for given value of Gibbs free energy, we use the relation:

where,

= standard Gibbs free energy = 149. kJ/mol = 149000 J/mol  (Conversion factor: 1 kJ = 1000 J )

R = Gas constant =

T = temperature =

= equilibrium constant at 10°C = ?

Putting values in above equation, we get:

Hence, the equilibrium constant for this reaction is

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