Apatient is receiving 3000 ml/day of a solution that con-
tains 5 g of dextrose (glucose) per 100 ml of solution. if
glucose provides 4 kcal/g of energy, how many kilocalo-
ries per day is the patient receiving from the glucose?

600 kCal/ day

Explanation:

You can solve this type of problems using proportions, with the rule of three.

Follow these steps:

1. Analyze the giving data

2. Organize it

3.Write the proportions  

4. Clear the value you are looking for

5. Solve the equations by multiplying or dividing

Now for the exercise:

You have the following data:

3000 mL Solution per 1 day > 3000 mL S

The concentration of the solution is  

5 g of dextrose per 100 mL  Solution > 5g D - 100 mL S

The glucose provides some specific energy

4 kCal per 1 g of dextrose > 4kCal - 1 g D

First find the total grams of  dextrose (glucose) given in one day.

3000 mL S - x g D?

 100 mL S - 5 g D

The grams of glucose given in one day

xg D? = 3000 mL S(5 g D)/100 mL S  

you also can cancel the units mL S

xg D? = 150 g D.

The grams given in one day of glucose are 150 g /day

Now find the total Energy in those grams:

4 kCal -      1 g D

x kCal?-150 g D

Clear x kCal?

x kCal? = 4kCal (150g D)/(1g D)

x kCal? = 600 kCal  remember is for one day!

so the answer is

The patient is receiving 600 kCal/day

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.