Based on the results of part a, based on the results of part a, blank is a stronger reducing agent than blank at 823 \rm k. in the first reaction above, \rm h2(g)blank\rm coo(s) and the value of \rm k is 67. in the fourth reaction, \rm co(g)blank\rm coo(s) and the value of \rm k is 480. the blank equilibrium constant for the fourth reaction indicates that products are blank favored than the products in the first reaction. is a stronger reducing agent than based on the results of part a, blank is a stronger reducing agent than blank at 823 \rm k. in the first reaction above, \rm h2(g)blank\rm coo(s) and the value of \rm k is 67. in the fourth reaction, \rm co(g)blank\rm coo(s) and the value of \rm k is 480. the blank equilibrium constant for the fourth reaction indicates that products are blank favored than the products in the first reaction. at 823 k
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Chemistry, 22.06.2019 08:30
What method(s) do plants use to obtain nitrogen? select all that apply. absorb it from the atmosphere use bacteria to convert nitrogen to usable form obtain usable nitrogen compounds from the soil absorb nitrogen from water taken in at the roots
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Chemistry, 22.06.2019 16:50
Answer asap need by wednesday morning explain how a buffer works, using an ethanoic acid/sodium ethanoate system including how the system resists changes in ph upon addition of a small amount of base and upon addition of a small amount of acid respectively. include the following calculations in your i. calculate the ph of a solution made by mixing 25cm3 0.1m ch3cooh and 40cm3 0.1m ch3coo-na+. [ka = 1.74 x 10-5 m] ii. calculate the ph following the addition of a 10cm3 portion of 0.08 m naoh to 500cm3 of this buffer solution. iii. calculate the ph following the addition of a 10cm3 portion of 0.08 m hcl to 200cm3 of the original buffer solution.
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Chemistry, 22.06.2019 21:50
Answer the questions about this reaction: nai(aq) + cl2(g) → nacl(aq) + i2(g) write the oxidation and reduction half-reactions: oxidation half-reaction: reduction half-reaction: based on the table of relative strengths of oxidizing and reducing agents (b-18), would these reactants form these products? write the balanced equation: answer options: a. 0/na -> +1/na+1e- b. nai(aq) + cl2(g) → nacl(aq) + i2(g) c. +1/na+1e- -> 0 /na d. -1/2i -> 0/i2+2e- e. no f. 4nai(aq) + cl2(g) → 4nacl(aq) + i2(g) g. 2nai(aq) + cl2(g) → 2nacl(aq) + i2(g) h. 4nai(aq) + 2cl2(g) → 4nacl(aq) + 2i2(g) i. nai(aq) + cl2(g) → nacl(aq) + i2(g) j. 0/cl2+2e -> -1/2cl- k. yes
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Chemistry, 23.06.2019 03:30
Select the correct lewis structure for fluorine which is group 7a element?
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Based on the results of part a, based on the results of part a, blank is a stronger reducing agent t...
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