find the mass in grams of 4.52
mol c20h42. use the molar masses: c = 12.0 g/mol; h = 1.0 g/mol.
ca. 15.3g
b. 8.09 g
c. 1.27 g
d. 2.54 g
check answer

Mass = 1274 .64 g it would be option C if it is converted into kilogram

1274 .64 / 1000 = 1.27 Kg

Explanation:

Given data:

Number of moles of C₂₀H₄₂ = 4.52 mol

Molar mass of carbon = 12 g/mol

Molar mass of hydrogen = 1.0 g/mol

Mass of C₂₀H₄₂ = ?

Solution:

Number of moles = mass / molar mass

Molar mass = 20× 12 + 42× 1.0 = 282 g/mol

Now we will put the values in formula:

Number of moles = mass / molar mass

4.52 mol = mass / 282 g /mol

Mass = 4.52 mol × 282 g/mol

Mass = 1274 .64 g

3 1/4 %

explanation:

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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