Determine the mass of carbon dioxide formed from the combustion of 50.0 g of c4h8. asap!

157.08g

Explanation:

50.0g C4H8 + 602 ---> 4C02 + 4H20

mass of 1 mole of C4H8 = 56g

50.0g of C4H8 = 50/56 = 0.8928 moles of C4H8

If each mole of C4H8 produces 4 moles of carbon dioxide, we have a 1:4 ratio

0.8928 moles of C4H8 give us (0.8928 x 4) = 3.57 moles of carbon dioxide

mass of 1 mole of carbon dioxide = 44g

mass of 3.57 moles of carbon dioxide = 157.08g

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

each chemical family is represented as a group or column on the periodic table. based on chemical properties, there are 6 types of chemical families. group 1 represents alkali metals, group 2 represents alkaline earth metals, groups 3 to 12 represent transition metals, groups 13 to 16 represent non-metals and other metals, group 17 represents halogens and group 18 represents noble gases.