Ammonia can be prepared by the reaction of magnesium nitride with water. the products are ammonia and magnesium hydroxide. write and balance the equation.

Mg3N2 +6H2O--> 2NH3 + 3Mg (OH)2

Mg3N2 + 6H20 → 2NH3  + 3Mg(OH)2

Explanation:

The reactant side(left side) of the equation is given as magnesium nitride and  water.

magnesium nitride  = combination of magnesium ion and nitrogen ion

Magnesium is the positive end or cation while Nitrogen is the anions or negative end

Mg2+  and  N3-

cross multiply the charges

Mg3N2 = magnesium nitride

H20 = water

Reactant = Mg3N2 + H20

Product  = NH3  + Mg(OH)2

For ammonia

N3- and H+

cross multiply the charges

NH3

For Magnesium hydroxide

Mg2+ and (OH)-

cross multiply the charges

Mg(OH)2

Combining the reactant and the product

Mg3N2 + H20 → NH3  + Mg(OH)2

Balancing the equation, we make the number of atom on the left side equal to the right side.

Mg3N2 + 6H20 → 2NH3  + 3Mg(OH)2

on the reactant side

Mg = 3

N = 2

H = 12

O = 6

On the product side

N  = 2

H = 6 + 6 = 12

Mg = 3

O = 6

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.