Identify the spectator ions in the following complete ionic equation.
ba
2+
(aq)+2
i
−
(aq)+2
na
+
(aq)+
so
2−
4
(aq)→
baso
4
(s)+2
i
−
(aq)+2
na
+
(aq)

2I⁻  and  2Na⁺  are spectator ions.

Explanation:

Ionic equation:

Ba⁺²(aq)  + 2I⁻(aq) + 2Na⁺(aq)  + SO₄²⁻ (aq)   →   BaSO₄(s)  +  2I⁻ (aq) + 2Na⁺(aq)

Net ionic equation:

Ba⁺²(aq)  + SO₄²⁻ (aq)   →   BaSO₄ (s)  

The I⁻ and Na⁺  are spectator ions that's why these are not written in net ionic equation. The BaSO₄ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.