In a laboratory, the balmer-beta spectral line of hydrogen has a wavelength of 486.1 nm. if the line appears in a star's spectrum at 486.4 nm, what is the star's radial velocity (in km/s)? (enter the magnitude.) km/s is it approaching or receding? approaching receding is this a blueshift or a redshift? blueshift redshift

185.15 km/s

It is receding, that's a redshift

Explanation:

The radial velocity V of a star can be calculated by the formula:

V = c·Δλ/λ₀

Where c is the speed of light (3*10⁸m/s), Δλ is the wavelength shift (the difference between the wavelengths), and λ₀ is the wavelength that is not shifted (in this problem, 486.1 nm)

If we put the given data in the equation we're left with:

V =

V = 185147.09 m/s

Converting the velocity to km/s:

= 185.15 km/s

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.