Consider the hypothetical reaction 3a + 4b → c + 2d over an interval of 2.50 s the average rate of change of the concentration of a was measured to be -0.0560 m/s. what is the final concentration of b at the end of this same interval if its concentration was initially 1.700 m?

Final [B] = 1.665 M

Explanation:

3A + 4B → C + 2D

Average rection rate = 3[A]/Δt = 4[B]/Δt = [C]/Δt = 2[D]/Δt

0.05600 M/s = 4 [B]/ 2.50 s

[B] = 0.035 M (concentration of B consumed)

Final [B] = initial [B] - consumed [B]

Final [B] = 1.700 M - 0.035 M

Final [B] = 1.665 M

it's c. elements are placed in rows based on how may valencies electrons have.

it takes on an electronical energy