Given that at 25.0 ∘c ka for hcn is 4.9×10−10 and kb for nh3 is 1.8×10−5, calculate kb for cn− and ka for nh4+. enter the kb value for cn− followed by the ka value for nh4+, separated by a comma, using two significant figures.

Explanation:

Using the expression :

Where, is the dissociation constant of water.

At ,

Thus, for HCN ,

for CN⁻ can be calculated as:

Thus, for NH₃ ,

for can be calculated as:

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.