Apurified protein is in a hepes (n‑(2‑hydroxyethyl)piperazine‑n‑(2‑ ethanesulfonic acid)) buffer at ph 7 with 800 mm nacl. a 1 ml sample of the protein solution is placed in a tube made of dialysis membrane and dialyzed against 1.0 l of the same hepes buffer with 0 mm nacl. small molecules and ions, such as na, cl, and hepes, can diffuse across the dialysis membrane, but the protein cannot. once the dialysis has come to equilibrium, what is the concentration of nacl in the protein sample? assume no volume changes occur in the sample during the dialysis.

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation:

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole