Using the following equation, determine the % yield from the following reaction if 30.65 g of octane (c_8 8 h_{18} 18 ) react with excess oxygen to produce 81.75 g of co_2 2 (g) 2c_8 8 h_{18} 18 (i) + 25o_2 2 (g) → 16co_2 2 (g) + 18h_2 2 o(l)

Now consider the reaction when 45.0 g naoh have been added. what amount of naoh is this, and what amount of fecl3 can be consumed by it?

1.aluminum chloride (alcl3), and sodium hydroxide (naoh) can react to form aluminum hydroxide (al(oh)3) and sodium chloride (nacl).    you have 13.4 g of aluminum chloride and 10.0 g of sodium hydroxide. answer the following questions: •what is the balanced equation for this reaction? •if you use all 13.4 g of aluminum chloride, how many grams of aluminum hydroxide can be formed? work must be shown to earn credit •if you use all 10.0 g of sodium hydroxide, how many grams of aluminum hydroxide can be formed? work must be shown to earn credit •how many grams of aluminum hydroxide will actually be made?     which reagent is limiting? explain your answer.

Which statement describes james chadwick’s discovery.