What is the correct equilibrium constant expression for the following heterogeneous equilibrium? 4hcl (g) + o2 (g) ⇄ 2h2o (l) + 2cl2 (g) view available hint(s) what is the correct equilibrium constant expression for the following heterogeneous equilibrium?
4hcl (g) + o2 (g) ⇄ 2h2o (l) + 2cl2 (g)
kc=[cl2]/[hcl][o2] kc=[hcl]4[o2]/[cl2]2
kc=[cl2]2[h2o]2/[hcl]4[o2]
kc=[cl2]2/[hcl]4[o2]

Kc=[Cl2]2/[HCl]4[O2]

Explanation:

For determinate the equillibrium constant, water and pure susbtances are not taken account on the calculus. In this case, water are present in the equation, so we have to remove it in the Kc determination.

elements make up everything, and they combine to make compounds.

the answer is c

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.