Calculate the volume a solution required toof provide the following: (a) 2.14 g of sodium chloridefrom a 0.270 m solution, (b) 4.30 g of ethanol from a1.50m solution, (c) 0.85 g of acetic acid (ch3cooh)from a 0.30 m solution.

A) NaCl = 58.44 g/mol

number of moles :  2.14 / 58.44 = 0.0366 moles

V = n / M  => 0.0366 / 0.270 = 0.1355 L 


b) C2H6O = 46.06 g/mol

number of moles :  4.30 / 46.06 = 0.0933 moles

V = n / M  => 0.0933 / 1.50 = 0.0622 L 


c) CH3COOH = 60.0 g/mol

number of moles :  0.85 / 60.0= 0.0141 moles

V = n / M  =>   0.0141 / 0.30 = 0.047 L 


hope this helps!

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