Chemistry, 09.10.2019 03:00 destiny465

H2so4 is an unusual diprotic acid in that the first dissociation is considered strong, but the second dissociation is weak. therefore, h2so4 only has ka2 = 1.2x10−2. consider an aqueous solution containing 0.010 m h2so4. calculate the concentration of so42− ions in this solution. calculate the concentration of hso4− ions in this solution. calculate the concentration of h3o+ ions the solution. enter each of your answers to two significant figures. do not use scientific notation.

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Answer from: koboshy23

Explanation:

As it is given that the initial concentration of sulfuric acid is 0.010 M.

Hence, the ICE table for first dissociation of sulfuric acid is as follows.

$H_{2}SO_{4} + H_{2}O \rightleftharpoons HSO^{-}_{4} + H_{3}O^{+}$

Initial: 0.010 0 0

Change: -0.010 +0.010 +0.010

Equilibrium: 0 0.010 0.010

When second dissociation of sulfuric acid occurs which is partial then the ICE table will be as follows.

$HSO^{-}_{4} + H_{2}O \rightleftharpoons SO^{2-}_{4} + H_{3}O^{+}$

Initial: 0.010 0 0.010

Change: -x +x +x

Equilibrium: 0.010 - x x 0.010 + x

Since, it is given that $K_{a} = 1.2 \times 10^{-2}$ . Hence, formula for $K_{a}$ is as follows.

$K_{a} = \frac{[SO^{2-}_{4}][H_{3}O^{+}]}{[HSO^{-}_{4}]}$

$1.2 \times 10^{-2} = \frac{x(0.010 + x)}{(0.010 - x)}$

$0.0012 \times (0.010 - x) = x(0.010 + x)$

$0.00012 - 0.012x = x^{2} + 0.010x$

x = 0.0045

Hence, by using the equilibrium concentrations from the table and value of x we get the following.

$[SO^{2-}_{4}]$ = x,

= 0.0045 M

$[HSO^{-}_{4}]$ = 0.010 - x

= 0.010 - 0.0045

= 0.0055 M

$[H_{3}O^{+}]$ = 0.010 + x

= 0.010 + 0.0045

= 0.0145 M

Answer from: Quest

explanation:

i think option no d is the correct answer

40 points and brainliest to anyone who can answer these

Answer from: Quest

For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

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H2so4 is an unusual diprotic acid in that the first dissociation is considered strong, but the secon...