Chemistry, 10.10.2019 18:10 lailabirdiemae

Aflask is filled with pcl5 to a pressure of 2.00 atm at 300°c and allowed to come to equilibrium according to the reaction: pcl5(g) ⇄ pcl3(g) + cl2(g) analysis shows the total pressure in the flask at equilibrium is 3.96 atm. calculate the equilibrium constant kp for the reaction.

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Answer from: anggelkevin100

96.04

Explanation:

Kp is defined for any reaction as:

aA(g) +bB(g) ⇌ cC(g) +dD(g)

$Kp= \frac{partial-pressure-of-products}{partial-pressure-of-reagents}$

$Kp= \frac{(P_{C})^{c}(P_{D})^{d}}{(P_{A})^{a}(P_{B})^{b}}$

For the reaction:

$PCl_{5}(g) equilibrium PCl_{3}(g) + Cl_{2}(g)$

Kp is:

$Kp=\frac{P_{PCl_{3}}*P_{Cl_{2}}}{P_{PCl_{5}}}$

P in the equation is the partial pressure for each specie in the equilibrium.

We know the total pressure for the system at the beginning is 2 atm. We can say that at the beginning we have just $PCl_{5}$ so the total pressure for the system is also the partial pressure for $PCl_{5}$

In the equilibrium we have the three species $PCl_{5}$ , $PCl_{3}$ and $Cl_{2}$ so now we need to estimate the partial pressure for each specie.

We know that the total pressure for the system in the equilibrium is 3.96 atm. The total pressure is equal to the sum of the partial pressure of each component in the mix as:

$P_{total}=P_ {PCl_{3}}+ P_{Cl_{2}}+ P_{PCl_{5}} = 3.96 atm$

Until we reach the equilibrium $PCl_{5}$ it’s been used to produce $PCl_{3}$ and $Cl_{2}$ . We can call (x) the among of $PCl_{5}$ that reacted until the system reach the equilibrium so $P_{PCl_{5}}$ in the equilibrium will be

$(P_{PCl_{5}}^{initial}) - x=P_{PCl_{5}}^{equilibrium}$

When reviewing the molar ratio in the reaction we see that it is 1: 1 so the amount of $PCl_{5}$ that reacted will be equal to the amount of $PCl_{3}$ and $Cl_{2}$ produced.

PCl5 Cl2 PCl3

Initial 2 atm 0 atm 0 atm

Equilibrium (2 atm - x)X atm X atm

Using the equation for total pressure:

$P_{total}= (2atm-x)+x+x = 3.96 atm$

solving we get that x = 1.96 atm.

This is the partial pressure for $PCl_{3}$ and $Cl_{2}$ in the equilibrium

For each component we have:

$P_{PCl_{5}}=2 atm - 1.96 atm = 0.04 atm$

$P_{PCl_{3}}= 1.96 atm$

$P_{Cl_{2}}= 1.96 atm$

$Kp=\frac{1.96 atm*1.96 atm}{0.04 atm}=96.04$

Answer from: Quest

chemical energy is stored in the chemical bonds of atoms and molecules. it can only be seen when it is released in a chemical reaction. when chemical energy is released, the substance from which the energy came is often changed into an entirely different substance.

this chemical reaction releases energy in the form of light and heat. chemical energy is the potential energy stored in the arrangement of atoms within molecules. breaking chemical bonds requires energy, while forming new chemical bonds releases energy.

the atp molecule can store energy in the form of a high energy phosphate bond joining the terminal phosphate group to the rest of the molecule. in this form,energy can be stored at one location, then moved from one part of the cell to another, where it can be released to drive other biochemical reactions.

Answer from: Quest

Ithink d hope that