In oxidative phosphorylation, electrons are passed from one electron carrier to another. the energy released is used to a. generate large amounts of nadh and fadh2 b. synthesize carbon dioxide c. pump protons (h⁺) across the mitochondrial membrane d. form atp during glycolysis

d. Form ATP during glycolysis.

Explanation:

During oxidative phosphorylation, an oxidation-reduction reactions will happen and the electrons transferred and energy released will be used in the conversion of adenosine diphosphate (ADP) into adenosine triphosphate (ATP).

This happens as a step of glycolysis, wich is the process in which the organism breaks gluscose molecules to obtain energy.

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the   per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:                   1 - α               α               α           = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

=  

or,

or,   = (at v = 1l)

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:               (1 - α)/0.5           α/0.5         α/0.5       = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

or,  

=  

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%

it is important to conserve water because there is very limited amount of freshwater here on earth and if we are not smart about how we use it we will only be runnning out of our supply faster than neccessarry.