Aball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2. what is the final velocity of the ball after 6.0 seconds? a. –9.6 meters/second b. 9.6 meters/second c. –19 meters/second d. 19 meters/second

D. 19 m/sec to the nearest whole number.

Explanation:

v = u + at   where u = initial  velocity, v = final velocity a = acceleration and t = time.

v = 0 + 3.2 * 6

= 19.2.

the correct answer would be d. hope this !

i believe the answer is true.