Achemist prepares a solution of fluoride (mgf2) by measuring out 0.0191 ųmol of magnesium fluoride into a 400. ml volumetric flask and filling the flask to the mark with water. calculate the concentration in mol/l of the chemist's magnesium fluoride solution.

The answer to your question is:  0.05 M

Explanation:

I'm not sure about the units umol, I think is units mol.

Data

MgF2 = 0.0191 mol

Volume = 400 ml

Molarity = moles / volume

Molarity = 0.0191 / 0.4 l

Molarity = 0.048 ≈ 0.05 M

hloride, what is the mass of calcium in

explanation: